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A day full of math games & activities. Find one near you.
Find the first six terms of the sequence. a1 = 7, an = an - 1 + 6
Solution:
Given, a1 = 7
an = an-1 + 6
We have to find the first six terms.
The given series is an arithmetic sequence, with a common difference of 6.
Here, a = 7
\(a_{2} = a_{2-1} + 6\\a_{2} = a_{1} + 6\\a_{2} = 7 + 6\\a_{2} =13\)
\(a_{3} = a_{3-1} + 6\\a_{3} = a_{2} + 6\\a_{3} = 13 + 6\\a_{2} = 19\)
\(a_{4} = a_{4-1} + 6\\a_{4}=a_{3} + 6\\a_{4} = 19 + 6\\a_{2} = 25\)
\(a_{5} = a_{5-1} + 6\\a_{5} = a_{4} + 6\\a_{5} = 25 + 6\\a_{2} = 31\)
\(a_{6} = a_{6-1} + 6\\a_{6} = a_{5} + 6\\a_{6} = 31+6\\a_{2} = 37\)
Therefore, the first six terms of the sequence are 7, 13, 19, 25, 31 and 37.
Find the first six terms of the sequence. a1 = 7, an = an - 1 + 6
Summary:
The first six terms of the sequence a1 = 7, an = an - 1 + 6 are 7, 13, 19, 25, 31 and 37.
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