Find the first partial derivatives of the function. f(x, y) = x7y?
Solution:
Given function is
f(x, y) = x7y
Since, it is an implicit function, we need to do implicit differentiation by finding partial derivatives
Partial derivative means differentiating w.r.t one variable keeping the other as a constant.
d(f(x, y)) = d(f(x, y))/dx + d(f(x, y))/dy
d(f(x, y)) = 7x6y + x7dy/dx
Hence, the partial derivative of the given implicit function is 7x6y + x7dy/dx
Find the first partial derivatives of the function. f(x, y) = x7y?
Summary:
The first partial derivatives of the function. f(x, y) = x7y is 7x6y + x7dy/dx
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