Find the equation of the line that passes through the given point (-4, 3) with slope 1/2.

Solution:

The equation of the line passing through a point with a given slope is found by using the formula

(y - y₁) = m(x - x₁)

Substituting the value of (-4,3) and slope 1/2 in above formula, we get

(y - 3) = 1/2 (x - (-4))

By further calculation 

(y - 3) = 1/2(x + 4)

By cross multiplication

2(y - 3) = (x + 4)

Using the multiplicative distributive property

2y - 6 = x + 4

On rearranging,

x - 2y + 10 = 0

Therefore, the equation of the line is x - 2y + 10 = 0.

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Find the equation of the line that passes through the given point (-4, 3) with slope 1/2.

Summary:

The equation of the line that passes through the given point (-4, 3) with slope 1/2 is x - 2y + 10 = 0.