Find a point on the line and the slope of the line.

Solution:

We may use the general equation of the line to understand the examples.

Let the equation of a line be, ax + by = c, where a,b,c are constants

Slope of the line = (negative coefficient of x) / ( coefficient of y )

slope = -b/a

Example: To find a point on the line, let us suppose x = 0

Therefore, y =c/b

So, a point on the line will be (0, c/b)

Suppose the equation of the line  is 2x + 3 y = 5

Therefore, using the above example, and comparing this equation of the line with the general equation i.e. ax + by = c

We get, a = 2, b = 3, c = 5

Thus, slope of this line = -b / a = -3/2 

Point lying on it will be, (0, c / b) = (0, 5 / 3)

Thus, the slope of the a line represented by c = ax + b is -b/a and one point on it is (0,c/b).

Find a point on the line and the slope of the line.

Summary:

The slope of the a line represented by c = ax + b is -b/a and one point on it is (0,c/b).