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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
Draw a graph of the rose curve. r = 4 cos 2θ, 0 ≤ θ ≤ 2π.
Solution:
The rose curve equation is of the form acos(nθ).
It is given that
r = 4 cos 2θ, 0 ≤ θ ≤ 2π
a= 4 and n = 2
Here n is even. Thus we have 2n petals = 4 petals. The separation between the petals is given as 360º/n = 360º/2 = 180º.
The table below shows the values of cos2θ that we plot between 0 and 2π.
θ |
2θ |
Cos 2θ |
0 |
0 |
1 |
π/6 |
π/3 |
1/2 |
π/4 |
π/2 |
0 |
π/3 |
2π/3 |
-√2/2 |
π/2 |
π |
-1 |
3π/4 |
3π/2 |
0 |
π |
2π |
1 |
5π/4 |
5π/2 |
0 |
3π/2 |
3π |
-1 |
7π/4 |
7π/2 |
0 |
2π |
4π |
1 |
Therefore, the graph of the rose curve is mentioned above.
Draw a graph of the rose curve. r = 4 cos 2θ, 0 ≤ θ ≤ 2π.
Summary:
The graph of the rose curve r = 4 cos 2θ, 0 ≤ θ ≤ 2π is mentioned above. It has 4 petals, separated by 180º.
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