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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
Determine the standard form of the equation of the line that passes through (-7, 8) and (0, 2).
Solution:
The standard equation of a line is Ax + By + C = 0.
Equation of the line in the two point form is (y - y1) = [(y2 - y1) / (x2 - x1)] (x - x1) ------(1)
Given that line passes through (-7, 8) and (0, 2)
∴ Substituting (x1, y1) = (-7, 8) and (x2, y2) = (0, 2) in equation (1),
(y - y1) = [(y2 - y1) / (x2 - x1)] (x - x1)
(y - 8) = [(2 - 8) / (0 - (-7)] [x - (-7)]
(y - 8) = (-6/ 7) (x + 7)
7y - 56 = -6x - 42
6x + 7y - 14 = 0
This is the required equation of the line which is in the general form.
Determine the standard form of the equation of the line that passes through (-7, 8) and (0, 2).
Summary:
The standard form of the equation of the line that passes through (-7, 8) and (0, 2) is 6x + 7y - 14 = 0.
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