By how much does the mean of the data set below change if the outlier is removed round your answer to the nearest tenth if necessary 8, 6, 9, 12, 19, 7, 10, 8?

Solution:

The given data set is as follows: 8, 6, 9, 12, 19, 7, 10, 8

The mean of the above numbers is = (8 + 6 + 9 + 12 + 19 + 7 + 10 + 8)/8 = 79/8 = 9.9

An outlier is a value which is not around the other values in the given data.

In the given problem the outlier is none other than the value of 19.

The average we calculated above is 9.9 and that too is distant from the value of 19.

Hence it is an outlier.

If we remove the outlier(19) from the data we have: 8, 6, 9, 12, 7, 10, 8

Mean = (8 + 6 + 9 + 12 + 7 + 10 + 8)/8 = 60/7 = 8.6

Without the outlier the mean of the given data falls from 9.9 to 8.6 which is a change of 1.3

Fall in the mean value of data = 9.9 - 8.6 = 1.3

Therefore, the fall in the mean value of data is 1.3

By how much does the mean of the data set below change if the outlier is removed round your answer to the nearest tenth if necessary 8, 6, 9, 12, 19, 7, 10, 8?

Summary:

The fall in the mean value of the given data 8, 6, 9, 12, 19, 7, 10, 8 if the outlier is removed is 1.3