An isosceles trapezoid has bases of 4 and 10. If the base angle is 45°, find the area.

Solution:

Given bases of trapezoid are 4, 10 and the base angle is 45°

Let a, b be the bases of the isosceles trapezoid

Here, a = 4, b = 10

We know that the general formula for the area of the trapezoid is

A=(a + b) × h/2 and the formula for the height is h =(b - a)/2

Height h = {b - a} /2 = 10 - 4 /2 = 6/2 = 3

Area = {(4 + 10) × 3} /2

Area = {14 × 3 }/2

Area = 42 /2 = 21

Area of the isosceles trapezoid is 21 sq. units.

An isosceles trapezoid has bases of 4 and 10. If the base angle is 45°, find the area.

Summary:

An isosceles trapezoid has bases of 4 and 10. If the base angle is 45°, its area is 21 sq.units.