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A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A day full of math games & activities. Find one near you.
A circle has a diameter with endpoints of (-2, 8) and (6, 4). What is the center of the circle?
Solution:
We know that
If a circle has a diameter with endpoints of (x1, y1) and (x2, y2) then the center has coordinates.
Using the midpoint formula we get the coordinates of the center as
((x\(_1\) + x\(_2\))/2, (y\(_1\) + y\(_2\))/2))
In the question, the endpoints of the circle are (-2, 8) and (6, 4)
Then the center of the circle =
((x\(_1\) + x\(_2\))/2, (y\(_1\) + y\(_2\))/2))
Substituting the values
= [(-2 + 6)/2, (8 + 4)/2]
= [4/2, 12/2]
= [2, 6]
Therefore, the center of the circle is [2, 6].
A circle has a diameter with endpoints of (-2, 8) and (6, 4). What is the center of the circle?
Summary:
A circle has a diameter with endpoints of (-2, 8) and (6, 4). The center of the circle is [2, 6].
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