A bag contains 25 paise coins, 50 paise coins, and 1 rupee coin whose values are in the ratio of 8:4:2. The total values of coins are 840. Then, find the total number of coins.

The problem can be solved using linear equations in one variable and ratio calculation.

Answer: The total number of coins is 2520.

Let's understand the terms in detail.

Explanation:

Given that the number of 25p, 50p, and Rs.1 coins are in the ratio 8 : 4 : 2

Let x be the  value of each portion

Then the value  of 25p coins is 8x, 50p coins is 4x, ₹1 coins is 2x. 

Then total value = 8x + 4x + 2 x = 14  x

Given the total  value = ₹ 840

14 x = ₹ 840

x = 840/14 = 60

The value of each portion is ₹ 60

25p coins make up 8 × 60 = ₹ 480

50p coins make up 4 × 60 = ₹ 240

₹ 1 coins make up 2 × 60 = ₹ 120

 Number of 25 p coins = 4 × 480 =1920 coins  

Number of 50 p coins = 2  × 240 = 480 coins 

Number of  ₹ 1 coin = 1  × 120 = 120 coins

Thus we have 1920 + 480 + 120 coins = 2520 coins

Thus, the total number of coins that the bag contains is 2520.