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LCM of 2, 4, 6, and 8

LCM of 2, 4, 6, and 8 is the smallest number among all common multiples of 2, 4, 6, and 8. The first few multiples of 2, 4, 6, and 8 are (2, 4, 6, 8, 10 . . .), (4, 8, 12, 16, 20 . . .), (6, 12, 18, 24, 30 . . .), and (8, 16, 24, 32, 40 . . .) respectively. There are 3 commonly used methods to find LCM of 2, 4, 6, 8 - by division method, by listing multiples, and by prime factorization.

1. LCM of 2, 4, 6, and 8
2. List of Methods
3. Solved Examples
4. FAQs

What is the LCM of 2, 4, 6, and 8?

Answer: LCM of 2, 4, 6, and 8 is 24.

LCM of 2, 4, 6, and 8

Explanation:

The LCM of four non-zero integers, a(2), b(4), c(6), and d(8), is the smallest positive integer m(24) that is divisible by a(2), b(4), c(6), and d(8) without any remainder.

Methods to Find LCM of 2, 4, 6, and 8

The methods to find the LCM of 2, 4, 6, and 8 are explained below.

  • By Listing Multiples
  • By Prime Factorization Method
  • By Division Method

LCM of 2, 4, 6, and 8 by Listing Multiples

To calculate the LCM of 2, 4, 6, 8 by listing out the common multiples, we can follow the given below steps:

  • Step 1: List a few multiples of 2 (2, 4, 6, 8, 10 . . .), 4 (4, 8, 12, 16, 20 . . .), 6 (6, 12, 18, 24, 30 . . .), and 8 (8, 16, 24, 32, 40 . . .).
  • Step 2: The common multiples from the multiples of 2, 4, 6, and 8 are 24, 48, . . .
  • Step 3: The smallest common multiple of 2, 4, 6, and 8 is 24.

∴ The least common multiple of 2, 4, 6, and 8 = 24.

LCM of 2, 4, 6, and 8 by Prime Factorization

Prime factorization of 2, 4, 6, and 8 is (2) = 21, (2 × 2) = 22, (2 × 3) = 21 × 31, and (2 × 2 × 2) = 23 respectively. LCM of 2, 4, 6, and 8 can be obtained by multiplying prime factors raised to their respective highest power, i.e. 23 × 31 = 24.
Hence, the LCM of 2, 4, 6, and 8 by prime factorization is 24.

LCM of 2, 4, 6, and 8 by Division Method

LCM of 2, 4, 6, and 8 by Division Method

To calculate the LCM of 2, 4, 6, and 8 by the division method, we will divide the numbers(2, 4, 6, 8) by their prime factors (preferably common). The product of these divisors gives the LCM of 2, 4, 6, and 8.

  • Step 1: Find the smallest prime number that is a factor of at least one of the numbers, 2, 4, 6, and 8. Write this prime number(2) on the left of the given numbers(2, 4, 6, and 8), separated as per the ladder arrangement.
  • Step 2: If any of the given numbers (2, 4, 6, 8) is a multiple of 2, divide it by 2 and write the quotient below it. Bring down any number that is not divisible by the prime number.
  • Step 3: Continue the steps until only 1s are left in the last row.

The LCM of 2, 4, 6, and 8 is the product of all prime numbers on the left, i.e. LCM(2, 4, 6, 8) by division method = 2 × 2 × 2 × 3 = 24.

☛ Also Check:

LCM of 2, 4, 6, and 8 Examples

  1. Example 1: Which of the following is the LCM of 2, 4, 6, 8? 12, 24, 5, 32.

    Solution:

    The value of LCM of 2, 4, 6, and 8 is the smallest common multiple of 2, 4, 6, and 8. The number satisfying the given condition is 24. ∴LCM(2, 4, 6, 8) = 24.

  2. Example 2: Find the smallest number that is divisible by 2, 4, 6, 8 exactly.

    Solution:

    The smallest number that is divisible by 2, 4, 6, and 8 exactly is their LCM.
    ⇒ Multiples of 2, 4, 6, and 8:

    • Multiples of 2 = 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, . . . .
    • Multiples of 4 = 4, 8, 12, 16, 20, 24, . . . .
    • Multiples of 6 = 6, 12, 18, 24, 30, 36, . . . .
    • Multiples of 8 = 8, 16, 24, 32, 40, 48, . . . .

    Therefore, the LCM of 2, 4, 6, and 8 is 24.

  3. Example 3: Find the smallest number which when divided by 2, 4, 6, and 8 leaves 1 as the remainder in each case.

    Solution:

    The smallest number exactly divisible by 2, 4, 6, and 8 = LCM(2, 4, 6, 8) ⇒ Smallest number which leaves 1 as remainder when divided by 2, 4, 6, and 8 = LCM(2, 4, 6, 8) + 1

    • 2 = 21
    • 4 = 22
    • 6 = 21 × 31
    • 8 = 23

    LCM(2, 4, 6, 8) = 23 × 31 = 24

    ⇒ The required number = 24 + 1 = 25.
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FAQs on LCM of 2, 4, 6, and 8

What is the LCM of 2, 4, 6, and 8?

The LCM of 2, 4, 6, and 8 is 24. To find the least common multiple (LCM) of 2, 4, 6, and 8, we need to find the multiples of 2, 4, 6, and 8 (multiples of 2 = 2, 4, 6, 8 . . . . 24 . . . . ; multiples of 4 = 4, 8, 12, 16, 24 . . . .; multiples of 6 = 6, 12, 18, 24 . . . .; multiples of 8 = 8, 16, 24, 32 . . . .) and choose the smallest multiple that is exactly divisible by 2, 4, 6, and 8, i.e., 24.

Which of the following is the LCM of 2, 4, 6, and 8? 24, 32, 12, 30

The value of LCM of 2, 4, 6, 8 is the smallest common multiple of 2, 4, 6, and 8. The number satisfying the given condition is 24.

How to Find the LCM of 2, 4, 6, and 8 by Prime Factorization?

To find the LCM of 2, 4, 6, and 8 using prime factorization, we will find the prime factors, (2 = 21), (4 = 22), (6 = 21 × 31), and (8 = 23). LCM of 2, 4, 6, and 8 is the product of prime factors raised to their respective highest exponent among the numbers 2, 4, 6, and 8.
⇒ LCM of 2, 4, 6, 8 = 23 × 31 = 24.

What is the Least Perfect Square Divisible by 2, 4, 6, and 8?

The least number divisible by 2, 4, 6, and 8 = LCM(2, 4, 6, 8)
LCM of 2, 4, 6, and 8 = 2 × 2 × 2 × 3 [Incomplete pair(s): 2, 3]
⇒ Least perfect square divisible by each 2, 4, 6, and 8 = LCM(2, 4, 6, 8) × 2 × 3 = 144 [Square root of 144 = √144 = ±12]
Therefore, 144 is the required number.

 
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