LCM of 2, 4, 6, 8, and 10
LCM of 2, 4, 6, 8, and 10 is the smallest number among all common multiples of 2, 4, 6, 8, and 10. The first few multiples of 2, 4, 6, 8, and 10 are (2, 4, 6, 8, 10 . . .), (4, 8, 12, 16, 20 . . .), (6, 12, 18, 24, 30 . . .), (8, 16, 24, 32, 40 . . .), and (10, 20, 30, 40, 50 . . .) respectively. There are 3 commonly used methods to find LCM of 2, 4, 6, 8, and 10 - by listing multiples, by division method, and by prime factorization.
1. | LCM of 2, 4, 6, 8, and 10 |
2. | List of Methods |
3. | Solved Examples |
4. | FAQs |
What is the LCM of 2, 4, 6, 8, and 10?
Answer: LCM of 2, 4, 6, 8, and 10 is 120.
Explanation:
The LCM of five non-zero integers, a(2), b(4), c(6), d(8), and e(10), is the smallest positive integer m(120) that is divisible by a(2), b(4), c(6), d(8), and e(10) without any remainder.
Methods to Find LCM of 2, 4, 6, 8, and 10
The methods to find the LCM of 2, 4, 6, 8, and 10 are explained below.
- By Prime Factorization Method
- By Listing Multiples
- By Division Method
LCM of 2, 4, 6, 8, and 10 by Prime Factorization
Prime factorization of 2, 4, 6, 8, and 10 is (2) = 21, (2 × 2) = 22, (2 × 3) = 21 × 31, (2 × 2 × 2) = 23, and (2 × 5) = 21 × 51 respectively. LCM of 2, 4, 6, 8, and 10 can be obtained by multiplying prime factors raised to their respective highest power, i.e. 23 × 31 × 51 = 120.
Hence, the LCM of 2, 4, 6, 8, and 10 by prime factorization is 120.
LCM of 2, 4, 6, 8, and 10 by Listing Multiples
To calculate the LCM of 2, 4, 6, 8, and 10 by listing out the common multiples, we can follow the given below steps:
- Step 1: List a few multiples of 2 (2, 4, 6, 8, 10, . . .120, . . .), 4 (4, 8, 12, 16, 20, . . .120, . . .), 6 (6, 12, 18, 24, 30, . . .120, . . .), 8 (8, 16, 24, 32, 40, . . ., 120, . . .), and 10 (10, 20, 30, 40, 50, . . ., 120, . . ).
- Step 2: The common multiples from the multiples of 2, 4, 6, 8, and 10 are 120, 240, . . .
- Step 3: The smallest common multiple of 2, 4, 6, 8, and 10 is 120.
∴ The least common multiple of 2, 4, 6, 8, and 10 = 120.
LCM of 2, 4, 6, 8, and 10 by Division Method
To calculate the LCM of 2, 4, 6, 8, and 10 by the division method, we will divide the numbers(2, 4, 6, 8, 10) by their prime factors (preferably common). The product of these divisors gives the LCM of 2, 4, 6, 8, and 10.
- Step 1: Find the smallest prime number that is a factor of at least one of the numbers, 2, 4, 6, 8, and 10. Write this prime number(2) on the left of the given numbers(2, 4, 6, 8, and 10), separated as per the ladder arrangement.
- Step 2: If any of the given numbers (2, 4, 6, 8, 10) is a multiple of 2, divide it by 2 and write the quotient below it. Bring down any number that is not divisible by the prime number.
- Step 3: Continue the steps until only 1s are left in the last row.
The LCM of 2, 4, 6, 8, and 10 is the product of all prime numbers on the left, i.e. LCM(2, 4, 6, 8, 10) by division method = 2 × 2 × 2 × 3 × 5 = 120.
☛ Also Check:
- LCM of 15, 25 and 30 - 150
- LCM of 50 and 75 - 150
- LCM of 6, 7 and 9 - 126
- LCM of 4, 6 and 12 - 12
- LCM of 3, 6 and 12 - 12
- LCM of 9 and 10 - 90
- LCM of 18 and 72 - 72
LCM of 2, 4, 6, 8, and 10 Examples
-
Example 1: Find the smallest number which when divided by 2, 4, 6, 8, and 10 leaves 1 as the remainder in each case.
Solution:
The smallest number exactly divisible by 2, 4, 6, 8, and 10 = LCM(2, 4, 6, 8, 10)
⇒ Smallest number which leaves 1 as remainder when divided by 2, 4, 6, 8, and 10 = LCM(2, 4, 6, 8, 10) + 1
- 2 = 21
- 4 = 22
- 6 = 21 × 31
- 8 = 23
- 10 = 21 × 51
LCM(2, 4, 6, 8, 10) = 23 × 31 × 51 = 120
⇒ The required number = 120 + 1 = 121. -
Example 2: Find the smallest number that is divisible by 2, 4, 6, 8, and 10 exactly.
Solution:
The value of LCM(2, 4, 6, 8, 10) will be the smallest number that is exactly divisible by 2, 4, 6, 8, and 10.
⇒ Multiples of 2, 4, 6, 8, and 10:- Multiples of 2 = 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, . . . 114, 116, 118, 120, . . .
- Multiples of 4 = 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, . . . 104, 108, 112, 116, 120, . . .
- Multiples of 6 = 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, . . . 102, 108, 114, 120, . . .
- Multiples of 8 = 8, 16, 24, 32, 40, 48, 56, 64, . . . 88, 96, 104, 112, 120, . . .
- Multiples of 10 = 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 110, 120, . . .
Therefore, the LCM of 2, 4, 6, 8, and 10 is 120.
-
Example 3: Which of the following is the LCM of 2, 4, 6, 8, 10? 105, 11, 120, 50.
Solution:
The value of LCM of 2, 4, 6, 8, and 10 is the smallest common multiple of 2, 4, 6, 8, and 10.
The number satisfying the given condition is 120.
∴LCM(2, 4, 6, 8, 10) = 120.
FAQs on LCM of 2, 4, 6, 8, and 10
What is the LCM of 2, 4, 6, 8, and 10?
The LCM of 2, 4, 6, 8, and 10 is 120. To find the least common multiple of 2, 4, 6, 8, and 10, we need to find the multiples of 2, 4, 6, 8, and 10 (multiples of 2 = 2, 4, 6, 8, . . . 120, . . .; multiples of 4 = 4, 8, 12, 16, . . .120, . . .; multiples of 6 = 6, 12, 18, 24 . . .120, . . .; multiples of 8 = 8, 16, 24, 32, . . .120, . . .; multiples of 10 = 10, 20, 30, 40, . . . 120, . . .) and choose the smallest multiple that is exactly divisible by 2, 4, 6, 8, and 10, i.e., 120.
How to Find the LCM of 2, 4, 6, 8, and 10 by Prime Factorization?
To find the LCM of 2, 4, 6, 8, and 10 using prime factorization, we will find the prime factors, (2 = 21), (4 = 22), (6 = 21 × 31), (8 = 23), and (10 = 21 × 51). LCM of 2, 4, 6, 8, and 10 is the product of prime factors raised to their respective highest exponent among the numbers 2, 4, 6, 8, and 10.
⇒ LCM of 2, 4, 6, 8, 10 = 23 × 31 × 51 = 120.
Which of the following is the LCM of 2, 4, 6, 8, and 10? 120, 15, 81, 30
The value of LCM of 2, 4, 6, 8, 10 is the smallest common multiple of 2, 4, 6, 8, and 10. The number satisfying the given condition is 120.
What are the Methods to Find LCM of 2, 4, 6, 8, and 10?
The commonly used methods to find the LCM of 2, 4, 6, 8, and 10 are:
- Listing Multiples
- Prime Factorization Method
- Division Method
visual curriculum