LCM of 12, 15, 18, and 27
LCM of 12, 15, 18, and 27 is the smallest number among all common multiples of 12, 15, 18, and 27. The first few multiples of 12, 15, 18, and 27 are (12, 24, 36, 48, 60 . . .), (15, 30, 45, 60, 75 . . .), (18, 36, 54, 72, 90 . . .), and (27, 54, 81, 108, 135 . . .) respectively. There are 3 commonly used methods to find LCM of 12, 15, 18, 27 - by division method, by listing multiples, and by prime factorization.
1. | LCM of 12, 15, 18, and 27 |
2. | List of Methods |
3. | Solved Examples |
4. | FAQs |
What is the LCM of 12, 15, 18, and 27?
Answer: LCM of 12, 15, 18, and 27 is 540.
Explanation:
The LCM of four non-zero integers, a(12), b(15), c(18), and d(27), is the smallest positive integer m(540) that is divisible by a(12), b(15), c(18), and d(27) without any remainder.
Methods to Find LCM of 12, 15, 18, and 27
The methods to find the LCM of 12, 15, 18, and 27 are explained below.
- By Listing Multiples
- By Prime Factorization Method
- By Division Method
LCM of 12, 15, 18, and 27 by Listing Multiples
To calculate the LCM of 12, 15, 18, 27 by listing out the common multiples, we can follow the given below steps:
- Step 1: List a few multiples of 12 (12, 24, 36, 48, 60 . . .), 15 (15, 30, 45, 60, 75 . . .), 18 (18, 36, 54, 72, 90 . . .), and 27 (27, 54, 81, 108, 135 . . .).
- Step 2: The common multiples from the multiples of 12, 15, 18, and 27 are 540, 1080, . . .
- Step 3: The smallest common multiple of 12, 15, 18, and 27 is 540.
∴ The least common multiple of 12, 15, 18, and 27 = 540.
LCM of 12, 15, 18, and 27 by Prime Factorization
Prime factorization of 12, 15, 18, and 27 is (2 × 2 × 3) = 22 × 31, (3 × 5) = 31 × 51, (2 × 3 × 3) = 21 × 32, and (3 × 3 × 3) = 33 respectively. LCM of 12, 15, 18, and 27 can be obtained by multiplying prime factors raised to their respective highest power, i.e. 22 × 33 × 51 = 540.
Hence, the LCM of 12, 15, 18, and 27 by prime factorization is 540.
LCM of 12, 15, 18, and 27 by Division Method
To calculate the LCM of 12, 15, 18, and 27 by the division method, we will divide the numbers(12, 15, 18, 27) by their prime factors (preferably common). The product of these divisors gives the LCM of 12, 15, 18, and 27.
- Step 1: Find the smallest prime number that is a factor of at least one of the numbers, 12, 15, 18, and 27. Write this prime number(2) on the left of the given numbers(12, 15, 18, and 27), separated as per the ladder arrangement.
- Step 2: If any of the given numbers (12, 15, 18, 27) is a multiple of 2, divide it by 2 and write the quotient below it. Bring down any number that is not divisible by the prime number.
- Step 3: Continue the steps until only 1s are left in the last row.
The LCM of 12, 15, 18, and 27 is the product of all prime numbers on the left, i.e. LCM(12, 15, 18, 27) by division method = 2 × 2 × 3 × 3 × 3 × 5 = 540.
☛ Also Check:
- LCM of 9 and 16 - 144
- LCM of 3, 4, 5 and 6 - 60
- LCM of 2 and 3 - 6
- LCM of 7 and 18 - 126
- LCM of 18 and 27 - 54
- LCM of 2 and 11 - 22
- LCM of 18 and 32 - 288
LCM of 12, 15, 18, and 27 Examples
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Example 1: Find the smallest number that is divisible by 12, 15, 18, 27 exactly.
Solution:
The value of LCM(12, 15, 18, 27) will be the smallest number that is exactly divisible by 12, 15, 18, and 27.
⇒ Multiples of 12, 15, 18, and 27:- Multiples of 12 = 12, 24, 36, 48, 60, 72, 84, 96, 108, 120, . . . ., 504, 516, 528, 540, . . . .
- Multiples of 15 = 15, 30, 45, 60, 75, 90, 105, 120, 135, 150, . . . ., 480, 495, 510, 525, 540, . . . .
- Multiples of 18 = 18, 36, 54, 72, 90, 108, 126, 144, 162, 180, . . . ., 468, 486, 504, 522, 540, . . . .
- Multiples of 27 = 27, 54, 81, 108, 135, 162, 189, 216, 243, 270, . . . ., 432, 459, 486, 513, 540, . . . .
Therefore, the LCM of 12, 15, 18, and 27 is 540.
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Example 2: Which of the following is the LCM of 12, 15, 18, 27? 24, 27, 30, 540.
Solution:
The value of LCM of 12, 15, 18, and 27 is the smallest common multiple of 12, 15, 18, and 27. The number satisfying the given condition is 540. ∴LCM(12, 15, 18, 27) = 540.
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Example 3: Find the smallest number which when divided by 12, 15, 18, and 27 leaves 1 as the remainder in each case.
Solution:
The smallest number exactly divisible by 12, 15, 18, and 27 = LCM(12, 15, 18, 27) ⇒ Smallest number which leaves 1 as remainder when divided by 12, 15, 18, and 27 = LCM(12, 15, 18, 27) + 1
- 12 = 22 × 31
- 15 = 31 × 51
- 18 = 21 × 32
- 27 = 33
LCM(12, 15, 18, 27) = 22 × 33 × 51 = 540
⇒ The required number = 540 + 1 = 541.
FAQs on LCM of 12, 15, 18, and 27
What is the LCM of 12, 15, 18, and 27?
The LCM of 12, 15, 18, and 27 is 540. To find the least common multiple of 12, 15, 18, and 27, we need to find the multiples of 12, 15, 18, and 27 (multiples of 12 = 12, 24, 36, 48 . . . . 540 . . . . ; multiples of 15 = 15, 30, 45, 60 . . . . 540 . . . . ; multiples of 18 = 18, 36, 54, 72 . . . . 540 . . . . ; multiples of 27 = 27, 54, 81, 108 . . . . 540 . . . . ) and choose the smallest multiple that is exactly divisible by 12, 15, 18, and 27, i.e., 540.
Which of the following is the LCM of 12, 15, 18, and 27? 2, 20, 540, 30
The value of LCM of 12, 15, 18, 27 is the smallest common multiple of 12, 15, 18, and 27. The number satisfying the given condition is 540.
What are the Methods to Find LCM of 12, 15, 18, 27?
The commonly used methods to find the LCM of 12, 15, 18, 27 are:
- Division Method
- Prime Factorization Method
- Listing Multiples
How to Find the LCM of 12, 15, 18, and 27 by Prime Factorization?
To find the LCM of 12, 15, 18, and 27 using prime factorization, we will find the prime factors, (12 = 22 × 31), (15 = 31 × 51), (18 = 21 × 32), and (27 = 33). LCM of 12, 15, 18, and 27 is the product of prime factors raised to their respective highest exponent among the numbers 12, 15, 18, and 27.
⇒ LCM of 12, 15, 18, 27 = 22 × 33 × 51 = 540.
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