Factors of 4950
Factors of 4950 are the list of integers that we can split evenly into 4950. It has total 36 factors of which 4950 is the biggest factor and the prime factors of 4950 are 2, 3, 5, 11. The sum of all factors of 4950 is 14508.
- All Factors of 4950: 1, 2, 3, 5, 6, 9, 10, 11, 15, 18, 22, 25, 30, 33, 45, 50, 55, 66, 75, 90, 99, 110, 150, 165, 198, 225, 275, 330, 450, 495, 550, 825, 990, 1650, 2475 and 4950
- Prime Factors of 4950: 2, 3, 5, 11
- Prime Factorization of 4950: 21 × 32 × 52 × 111
- Sum of Factors of 4950: 14508
1. | What Are the Factors of 4950? |
2. | Factors of 4950 by Prime Factorization |
3. | Factors of 4950 in Pairs |
4. | FAQs on Factors of 4950 |
What are Factors of 4950?
Factors of 4950 are pairs of those numbers whose products result in 4950. These factors are either prime numbers or composite numbers.
How to Find the Factors of 4950?
To find the factors of 4950, we will have to find the list of numbers that would divide 4950 without leaving any remainder.
- 4950/15 = 330; therefore, 15 is a factor of 4950 and 330 is also a factor of 4950.
- 4950/150 = 33; therefore, 150 is a factor of 4950 and 33 is also a factor of 4950.
☛ Also Check:
- Factors of 41 - The factors of 41 are 1, 41
- Factors of 99 - The factors of 99 are 1, 3, 9, 11, 33, 99
- Factors of 84 - The factors of 84 are 1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84
- Factors of 5 - The factors of 5 are 1, 5
- Factors of 180 - The factors of 180 are 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, 180
Factors of 4950 by Prime Factorization
- 4950 ÷ 2 = 2475
Further dividing 2475 by 2 gives a non-zero remainder. So we stop the process and continue dividing the number 2475 by the next smallest prime factor. We stop ultimately if the next prime factor doesn't exist or when we can't divide any further.
So, the prime factorization of 4950 can be written as 21 × 32 × 52 × 111 where 2, 3, 5, 11 are prime.
Factors of 4950 in Pairs
Pair factors of 4950 are the pairs of numbers that when multiplied give the product 4950. The factors of 4950 in pairs are:
- 1 × 4950 = (1, 4950)
- 2 × 2475 = (2, 2475)
- 3 × 1650 = (3, 1650)
- 5 × 990 = (5, 990)
- 6 × 825 = (6, 825)
- 9 × 550 = (9, 550)
- 10 × 495 = (10, 495)
- 11 × 450 = (11, 450)
- 15 × 330 = (15, 330)
- 18 × 275 = (18, 275)
- 22 × 225 = (22, 225)
- 25 × 198 = (25, 198)
- 30 × 165 = (30, 165)
- 33 × 150 = (33, 150)
- 45 × 110 = (45, 110)
- 50 × 99 = (50, 99)
- 55 × 90 = (55, 90)
- 66 × 75 = (66, 75)
Negative pair factors of 4950 are:
- -1 × -4950 = (-1, -4950)
- -2 × -2475 = (-2, -2475)
- -3 × -1650 = (-3, -1650)
- -5 × -990 = (-5, -990)
- -6 × -825 = (-6, -825)
- -9 × -550 = (-9, -550)
- -10 × -495 = (-10, -495)
- -11 × -450 = (-11, -450)
- -15 × -330 = (-15, -330)
- -18 × -275 = (-18, -275)
- -22 × -225 = (-22, -225)
- -25 × -198 = (-25, -198)
- -30 × -165 = (-30, -165)
- -33 × -150 = (-33, -150)
- -45 × -110 = (-45, -110)
- -50 × -99 = (-50, -99)
- -55 × -90 = (-55, -90)
- -66 × -75 = (-66, -75)
NOTE: If (a, b) is a pair factor of a number then (b, a) is also a pair factor of that number.
Factors of 4950 Solved Examples
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Example 1: How many factors are there for 4950?
Solution:
The factors of 4950 are too many, therefore if we can find the prime factorization of 4950, then the total number of factors can be calculated using the formula shown below.
If the prime factorization of the number is ax × by × cz where a, b, c are prime, then the total number of factors can be given by (x + 1)(y + 1)(z + 1).
Prime Factorization of 4950 = 21 × 32 × 52 × 111
Therefore, the total number of factors are (1 + 1) × (2 + 1) × (2 + 1) × (1 + 1) = 2 × 3 × 3 × 2 = 36 -
Example 2: Find the Least Common Multiple (LCM) and Greatest Common Factor (GCF) of 4950 and 1122.
Solution:
The factors of 4950 are 1, 2, 3, 5, 6, 9, 10, 11, 15, 18, 22, 25, 30, 33, 45, 50, 55, 66, 75, 90, 99, 110, 150, 165, 198, 225, 275, 330, 450, 495, 550, 825, 990, 1650, 2475, 4950 and factors of 1122 are 1, 2, 3, 6, 11, 17, 22, 33, 34, 51, 66, 102, 187, 374, 561, 1122.
Therefore, the Least Common Multiple (LCM) of 4950 and 1122 is 84150 and Greatest Common Factor (GCF) of 4950 and 1122 is 66. -
Example 3: Find if 1, 3, 11, 30, 66, 75, 225 and 334 are factors of 4950.
Solution:
When we divide 4950 by 334 it leaves a remainder. Therefore, the number 334 is not a factor of 4950. All numbers except 334 are factors of 4950.
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Example 4: Find the product of all the prime factors of 4950.
Solution:
Since, the prime factors of 4950 are 2, 3, 5, 11. Therefore, the product of prime factors = 2 × 3 × 5 × 11 = 330.
FAQs on Factors of 4950
What are the Factors of 4950?
The factors of 4950 are 1, 2, 3, 5, 6, 9, 10, 11, 15, 18, 22, 25, 30, 33, 45, 50, 55, 66, 75, 90, 99, 110, 150, 165, 198, 225, 275, 330, 450, 495, 550, 825, 990, 1650, 2475, 4950 and its negative factors are -1, -2, -3, -5, -6, -9, -10, -11, -15, -18, -22, -25, -30, -33, -45, -50, -55, -66, -75, -90, -99, -110, -150, -165, -198, -225, -275, -330, -450, -495, -550, -825, -990, -1650, -2475, -4950.
What is the Sum of all Factors of 4950?
Sum of all factors of 4950 = (21 + 1 - 1)/(2 - 1) × (32 + 1 - 1)/(3 - 1) × (52 + 1 - 1)/(5 - 1) × (111 + 1 - 1)/(11 - 1) = 14508
What are Prime Factors of 4950?
The prime factors of 4950 are 2, 3, 5, 11.
What is the Greatest Common Factor of 4950 and 3385?
The factors of 4950 and 3385 are 1, 2, 3, 5, 6, 9, 10, 11, 15, 18, 22, 25, 30, 33, 45, 50, 55, 66, 75, 90, 99, 110, 150, 165, 198, 225, 275, 330, 450, 495, 550, 825, 990, 1650, 2475, 4950 and 1, 5, 677, 3385 respectively.
Common factors of 4950 and 3385 are [1, 5].
Hence, the Greatest Common Factor of 4950 and 3385 is 5.
What are the Common Factors of 4950 and 2543?
Since, the factors of 4950 are 1, 2, 3, 5, 6, 9, 10, 11, 15, 18, 22, 25, 30, 33, 45, 50, 55, 66, 75, 90, 99, 110, 150, 165, 198, 225, 275, 330, 450, 495, 550, 825, 990, 1650, 2475, 4950 and factors of 2543 are 1, 2543. Hence, 4950 and 2543 have only one common factor which is 1. Therefore, 4950 and 2543 are co-prime.
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