Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse x2/4 + y2/25 = 1
Solution:
The given equation is x2/4 + y2/25 = 1
Here, the denominator of y2/25 is greater than the denominator of x2/4
Therefore, the major axis is along the y-axis, while the minor axis is along the x-axis.
On comparing the given equation with x2/b2 + y2/a2 = 1 we obtain b = 2 and a = 5
Hence,
c = √a² - b²
= √25 - 4
= √21
Therefore,
The coordinates of the foci are (0, ± √21)
The coordinates of the vertices are (0, ± 5)
Length of major axis = 2a = 10
Length of minor axis = 2b = 4
Eccentricity, e = c/a = √21/5
Length of latus rectum = 2b2/a = (2 × 4)/5 = 8/5
NCERT Solutions Class 11 Maths Chapter 11 Exercise 11.3 Question 2
Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse x2/4 + y2/25 = 1
Summary:
The coordinates of the foci and vertices are (0, ± √21), (0, ± 5) respectively. The length of the major axis, minor axis, and latus rectum are 10, 4, 8/5 respectively
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