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x/a + y/b = a + b. x/a² + y/b² = 2, a,b ≠ 0, solve the equation

Solution:

From the above question, we have the equation as,

x/a + y/b = a + b-------------(1)

x/a² + y/b² = 2----------------(2)

Multiplying (1) by 1/a and then subtracting from(2),we get,

y(1/b² - 1/ab) = 2 - 1 -b/a

y(a - b/ab²) = 1- b/a = (a - b/a)

y = ab²/a

y = b²

Substituting the value of y in the equation (2),we get,

x/a² + b²/b² = 2

x/a² = 2-1 = 1

x = a².

x = a², y = b²

Therefore, the required values of x and y are a² and b², respectively.

✦ Try This: Solve the following equation: x/a - y/b = a + b. x/a² - y/b² = 2, a,b ≠ 0

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 3

NCERT Exemplar Class 10 Maths Exercise 3.3 Problem 9 (vi)

Summary:

Solving the following equation x/a + y/b = a + b, x/a² + y/b² = 2, we get the required values of x and y as a² and b², respectively.

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