Write the first five terms of the sequences whose nth term is a_n = n (n² + 5)/4

Solution:

nth term is given as: a_n = n (n² + 5)/4

Substituting n = 1, 2, 3, 4, 5

a₁ = 1 (1² + 5)/4 = 3/2

a₂ = 2 (2² + 5)/4 = 9/2

a₃ = 3 (3² + 5)/4 = 21/2

a₄ = 4 (4² + 5)/4 = 21

a₅ = 5 (5² + 5)/4 = 75/2

Therefore, the required terms are 3/2, 9/2, 21/2, 21, 75/2

NCERT Solutions Class 11 Maths Chapter 9 Exercise 9.1 Question 6

Write the first five terms of the sequences whose nth term is a_n = n (n² + 5)/4

Summary:

The question tells us that the nth term is a_n = n (n² + 5)/4. Therefore the terms are 3/2, 9/2, 21/2, 21, 75/2