Write the coefficient of x² of the following : (π/6)x + x² + 1

Solution:

Given, the polynomial is (π/6)x + x² + 1

We have to find the coefficient of x².

The coefficient of x² in (π/6)x + x² + 1 is 1

Therefore, the coefficient of x² = 1

✦ Try This: Write the coefficient of x² of the following : (π/6)x + 7x² + 1

Given, the polynomial is (π/6)x + 7x² + 1

We have to find the coefficient of x².

The coefficient of x² in (π/6)x + 7x² + 1 is 7

Therefore, the coefficient of x² = 7

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2

NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 4(i)

Write the coefficient of x² of the following : (π/6)x + x² + 1

Summary:

The highest sum of the exponents is known as the degree of a polynomial. The coefficient of x² in the polynomial (π/6)x + x² + 1 is 1

☛ Related Questions:

• Write the coefficient of x² of the following : 3x - 5
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• Write the coefficient of x² of the following : (2x -5) (2x² - 3x + 1)