Write the additive inverse of each of the following
(i) 2/8    (ii) -5/9    (iii) -6/-5    (iv) 2/-9    (v) 19/-6

Solution:

The negative of a rational number is known as its additive inverse. The sum of a rational number and its additive number is equal to 0.

(i) Additive Inverse of 2/8 is

-(2/8) = -2/8

We see that, 2/8 + (-2/8) = 0

(ii) Additive Inverse of -5/9 is

- (-5/9) = 5/9

We see that, -5/9 + 5/9 = 0

(iii) Additive Inverse of -6/-5 is

-(-6/-5) = - (6/5) = - 6/5

We see that, -6/-5 + (-6/5) = 6/5 - 6/5 = 0

(iv) Additive Inverse of 2/-9 is

-(2/-9) = - (-2/9) = 2/9

We see that, 2/-9 + 2/9 = -2/9 + 2/9 = 0

(v) Additive Inverse of 19/-6 is

-(19/-6) = - (-19/6) = 19/6

We see that, 19/-6 + 19/6 = -19/6 + 19/6 = 0

☛ Check: Class 8 Maths NCERT Solutions Chapter 1

Video Solution:

Write the additive inverse of each of the following (i) 2/8 (ii) -5/9 (iii) -6/-5 (iv) 2/-9 (v) 19/-6

NCERT Solutions Class 8 Maths Chapter 1 Exercise 1.1 Question 2

Summary:

The additive inverses for (i) 2/8, (ii) -5/9, (iii) -6/-5, (iv) 2/-9, (v) 19/-6 are -2/8, 5/9, -6/5, 2/9, and 19/6 respectively

☛ Related Questions:

• Verify that -(-x) = x for. (i) x = 11/15 (ii) x = -13/7
• Find the multiplicative inverse of the following (i) -13 (ii) -13/19 (iii) 1/5 (iv) -5/8 × -3/7 (v) -1 × -2/5 (vi) -1.
• Name the property under multiplication used in each of the following: (i) -4/5 × 1 = 1 × -4/5 = -4/5 (ii) -13/17 × -2/7 = -2/7 × -13/17 (iii) -19/29 × 29/-19 = 1
• Multiply 6/13 by the reciprocal of -7/16. The multiplicative inverse of a number is defined as a number which when multiplied by the original number gives the product an identity