Write cubes of first three multiples of 3.

Solution:

We have to write the cube of first three multiples of 3.

First 3 multiples of 3 are

3 × 1 = 3

3 × 2 = 6

3 × 3 = 9

Number obtained when a number is multiplied by itself three times is called a cube number.

If m = n³, then m is a perfect cube where m and n are natural numbers.

Cube of 3 = 3³ = 27

Cube of 6 = 6³ = 216

Cube of 9 = 9³ = 729

Therefore, the required cubes are 27, 216 and 729.

✦ Try This: Write squares of first three multiples of 5.

☛ Also Check: NCERT Solutions for Class 8 Maths

NCERT Exemplar Class 8 Maths Chapter 3 Problem 88

Write cubes of first three multiples of 3

Summary:

The cubes of the first three multiples of 3 are 27, 216 and 729.

☛ Related Questions:

• Show that 500 is not a perfect square
• Express 81 as the sum of the first nine consecutive odd numbers
• Using prime factorisation, find the following is a perfect square : 484