Work out the surface area of the solid shape given below (use π = 3.14).
Solution:
The total surface area of the solid is the sum of the surface areas of two solid shapes i.e. 1) Cylinder and b) Cube
Surface Area of Cube = 6(s)²
Where s = length of the edge of the cube = 5cm
Surface Area of the cube = 6(5)² - π(2)² = 150 - 4π
Surface Area of the cylinder = 2πrh + πr² = 2 × π × 2 × 20 + π(2)² = 80π + 4π = 84π
Total Surface of the Area = 150 - 4π + 84π = 150 + 80π = 150 + 251.2 = 401.2cm².
✦ Try This: Find the surface area of the given solid shape.
The total surface area of the solid is the sum of the surface areas of two solid shapes i.e. 1) Cylinder and b) Cube
Surface Area of Cube = 6(s)²
Where s = length of the edge of the cube = 3cm
Surface Area of the cube = 6(3)² - π(1)² = 54 - π
Surface Area of the cylinder = 2πrh + πr² = 2 × π × 1 × 15 + π(1)² = 30π + π = 31π
Total Surface of the Area = 54 - π + 31π = 54 + 30π = 54 + 94.2 = 148.2cm².
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 11
NCERT Exemplar Class 8 Maths Chapter 11 Problem 124
Work out the surface area of the solid shape given below (use π= 3.14).
Summary:
The total surface area of the given solid is 401.2cm²
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