Verify: [(3p/7) + (7/6p)]² - [(3p/7) + (7/6p)]² = 2
Solution:
Given,[(3p/7) + (7/6p)]² - [(3p/7) + (7/6p)]² = 2
L.H.S = [(3p/7) + (7/6p)]² - [(3p/7) + (7/6p)]²
= [(3p/7)² + 2(3p/7)(7/6p) + (7/6p)²] - [(3p/7)² + 2(3p/7)(7/6p) + (7/6p)²]
= (3p/7)² + 2(3p/7)(7/6p) + (7/6p)² - (3p/7)² - 2(3p/7)(7/6p) - (7/6p)²
= 0 ≠ R.H.S
L.H.S. ≠ R.H.S.
✦ Try This:Verify: [(3x/5) + (5y/3)]² - [(3x/5) - (5y/3)]² = 4xy
Given, [(3x/5) + (3y/5)]² - [(3x/5) - (3y/5)]² = 4xy
L.H.S = [(3x/5) + (5y/3)]² - [(3x/5) - (5y/3)]²
= (3x/5)² + 2(3x/5)(5y/3) + (5y/3)² - [(3x/5)² - 2(3x/5)(5y/3) + (5y/3)²]
= (9x²/25) + (2xy) + (25y²/9) - (9x²/25) + (2xy) - (25y²/9)
= 4xy
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9
NCERT Exemplar Class 8 Maths Chapter 7 Problem 113(x)
Verify: [(3p/7) + (7/6p)]² - [(3p/7) + (7/6p)]² = 2
Summary:
[(3p/7) + (7/6p)]² - [(3p/7) - (7/6p)]² = 2 is not true
☛ Related Questions:
visual curriculum