Using the given pattern, find the missing numbers
1² + 2² + 2² = 3²
2² + 3² + 6² = 7²
3² + 4² + 12² = 13²
4² + 5² + _² = 21²
5² + _² + 30² = 31²
6² + 7² + _² = _²

Solution:

Let's find the missing squares in the pattern

The third number is the product of the first two numbers and the fourth number is obtained by adding 1 to the third number

1² + 2² + 2² = 3²

2² + 3² + 6² = 7²

3² + 4² + 12² = 13²

4² + 5² + 20² = 21²

5² + 6² + 30² = 31²

6² + 7² + 42² = 43²

☛ Check: NCERT Solutions for Class 8 Maths Chapter 6

Video Solution:

Using the given pattern, find the missing numbers. 1² + 2² + 2² = 3² . 2² + 3² + 6² = 7². 3² + 4² + 12² = 13² . 4² + 5² + _² = 21² . 4² + 5² + _² = 21² . 5² + -² + 30² = 31² . 6² + 7² + _² = _² 

NCERT Solutions for Class 8 Maths Chapter 6 Exercise 6.1 Question 6

Using the given pattern, find the missing numbers
1² + 2² + 2² = 3²
2² + 3² + 6² = 7²
3² + 4² + 12² = 13² 
4² + 5² + _² = 21²
4² + 5² + _² = 21² 
5² + _² + 30² = 31² 
6² + 7² + _² = _²

Summary:

For the given pattern, 1² + 2² + 2² = 3²  2² + 3² + 6² = 7²  3² + 4² + 12² = 13²   4² + 5² + _² = 21²  4² + 5² + _² = 21²   5² + _² + 30² = 31²   6² + 7² + _² = _², the missing squares in the pattern are 20, 6 and 42 respectively.

☛ Related Questions:

• Without adding, find the sum. (i) 1 + 3 + 5 + 7 + 9 (ii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 +19 (iii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23
• (i) Express 49 as the sum of 7 odd numbers. (ii) Express 121 as the sum of 11 odd numbers.
• How many numbers lie between squares of the following numbers? (i) 12 and 13 (ii) 25 and 26 (iii) 99 and 100
• Observe the following pattern and supply the missing numbers. 112 = 121 1012 = 10201 101012 = 102030201 10101012 = ? ?2 = 10203040504030201