Using suitable identity, evaluate the following : 103³
Solution:
Given, 103³
We have to evaluate the given expression using a suitable identity.
103³ = (100 + 3)³
Using algebraic identity,
(a + b)³ = a³ + b³ + 3ab(a + b)
(100 + 3)³ = (100)³ + (3)³ + 3(100)(3)(100 + 3)
= 1000000 + 27 + 900(103)
= 1000027 + 92700
= 1092727
Therefore, 103³ = 1092727
✦ Try This: Using suitable identity, evaluate the following : 102³
Given, 102³
We have to evaluate the given expression using a suitable identity.
102³ = (100 + 2)³
Using algebraic identity,
(a + b)³ = a³ + b³ + 3ab(a + b)
(100 + 2)³ = (100)³ + (2)³ + 3(100)(2)(100 + 2)
= 1000000 + 8 + 600(102)
= 1000008 + 61200
= 1061208
Therefore, 102³ = 1061208
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 2
NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 25(i)
Using suitable identity, evaluate the following : 103³
Summary:
The general expressions containing variables of varying degrees, coefficients, positive exponents, and constants are known as polynomial functions. On evaluating, the value of 103³ is 1092727
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