Use elimination method to find all possible solutions of the following pair of linear equations :
2x + 3y = 8 (1)
4x + 6y = 7(2)

Solution:

Let us use the elimination method to solve the pair of linear equations.

Given 2x + 3y = 8 be equation (1) and 4x + 6y = 7 be equation (2).

Step 1: Multiply equation 1 by 2.

⇒ 4x + 6y = 16 be equation 3.

Step 2: Subtract equation 3 from equation 2

⇒ (4x + 6y = 16 ) - (4x + 6y = 7)

⇒ (4x - 4x) + (6y - 6y) = (16 - 7)

⇒ 0 = 9

This is a false statement.

Thus, there are no common solutions to the pair of linear equations.

☛ Check: NCERT Solutions for Class 10 Maths Chapter 3

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Use elimination method to find all possible solutions of the following pair of linear equations : 2x + 3y = 8 (1) 4x + 6y = 7(2)

Summary:

The pair of linear equations 2x + 3y = 8 and 4x + 6y = 7 has no solution

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