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Two dice are thrown together. Find the probability that the product of the numbers on the top of the dice is 6

Solution:

Given, two dice are thrown together.

We have to find the probability that the product of the numbers on the top of the dice is 6.

When 2 dice are thrown at the same time, the overall possible outcomes are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total number of possible outcomes = 36

Favourable outcome = {(1,6) (2,3) (3,2) (1,6)}

Number of favourable outcomes = 4

Number of possible outcomes = 36

Probability = number of favourable outcomes / number of possible outcomes

Probability of getting a sum of 7 = 4/36

= 1/9

Therefore, the probability of getting the product of the numbers as 6 on the top of the dice is 1/9.

✦ Try This: Two dice are thrown together. Find the probability that the product of the numbers on the top of the dice is 8.

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 14

NCERT Exemplar Class 10 Maths Exercise 13.3 Problem 21(i)

Summary:

Two dice are thrown together. The probability that the product of the numbers on the top of the dice is 6 is 1/9

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