To draw a pair of tangents to a circle which are inclined to each other at an angle of 60°, it is required to draw tangents at end points of those two radii of the circle, the angle between them should be
a. 135°
b. 90°
c. 60°
d. 120°
Solution:
It is given that
O is the centre of a circle to which a pair of tangents PQ and PR from the point P touches the circle at Q and R
∠RPQ = 60°
We know that
∠OQP = 90° = ∠ORP
The angle between a tangent to a circle and the radius of the same circle passing through the point of contact is 90°
Using the angle sum property of quadrilaterals
∠OQP + ∠RPQ + ∠ORP + ∠ROQ = 360°
Substituting the values
90° + 60° + 90° + ∠ROQ = 360°
∠ROQ = 120°
Therefore, the angle between them should be 120°.
✦ Try This: To draw a pair of tangents to a circle which are inclined to each other at an angle of 40°, it is required to draw tangents at end points of those two radii of the circle, the angle between them should be
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 11
NCERT Exemplar Class 10 Maths Exercise 10.1 Problem 6
To draw a pair of tangents to a circle which are inclined to each other at an angle of 60°, it is required to draw tangents at end points of those two radii of the circle, the angle between them should be a. 135°, b. 90°, c. 60°, d. 120°
Summary:
To draw a pair of tangents to a circle which are inclined to each other at an angle of 60°, it is required to draw tangents at end points of those two radii of the circle, the angle between them should be 120°
☛ Related Questions:
- By geometrical construction, it is possible to divide a line segment in the ratio 2 + √3: 2 - √3. Wr . . . .
- By geometrical construction, it is possible to divide a line segment in the ratio √3: 1/√3. Write ‘T . . . .
- To construct a triangle similar to a given ∆ABC with its sides 7/3 of the corresponding sides of ∆AB . . . .
visual curriculum