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To construct a triangle similar to a given ∆ABC with its sides 8/5 of the corresponding sides of ∆ABC draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is
a. 5
b. 8
c. 13
d. 3

Solution:

We know that

In order to construct a triangle which is similar to a given triangle, with its sides x/y of the corresponding sides of the triangle, the minimum number of points to be located at equal distance is equal to the greater of m and n in m/n

In this question,

m: n = 8: 5

m/n = 8/5

Therefore, the minimum number of points to be located is 8.

✦ Try This: To construct a triangle similar to a given ∆ABC with its sides 7/5 of the corresponding sides of ∆ABC draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is

We know that

In order to construct a triangle which is similar to a given triangle, with its sides x/y of the corresponding sides of the triangle, the minimum number of points to be located at equal distance is equal to the greater of m and n in m/n

In this question,

m: n = 7: 5

m/n = 7/5

Therefore, the minimum number of points to be located is 5.

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 11

NCERT Exemplar Class 10 Maths Exercise 10.1 Problem 5

To construct a triangle similar to a given ∆ABC with its sides 8/5 of the corresponding sides of ∆ABC draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is a. 5, b. 8, c. 13, d. 3

Summary:

To construct a triangle similar to a given ∆ABC with its sides 8/5 of the corresponding sides of ∆ABC draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is 8

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