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To construct a triangle similar to a given ∆ABC with its sides 3/7 of the corresponding sides of ∆ABC, first draw a ray BX such that ∠CBX is an acute angle and X lies on the opposite side of A with respect to BC. Then locate points B₁ , B₂ , B₃ , ... on BX at equal distances and next step is to join
a. B₁₀to C
b. B₃to C
c. B₇to C
d. B₄to C

Solution:

In order to construct a triangle similar to a given ∆ABC with its sides 3/7 we have to divide BC in the ratio 3 : 7

BX should have 7 equidistant points on it as 7 is a greater number

Now we have to join B₇ to C.

To construct a triangle similar to a given ∆ABC with its sides 3/7 of the corresponding sides of ∆ABC, first draw a ray BX such that ∠CBX is an acute angle and X lies on the opposite side of A with respect to BC. Then locate points B1 , B2 , B3 , ... on BX at equal distances and next step is to join

Therefore, the next step is to join B₇ to C.

✦ Try This: To construct a triangle similar to a given ∆ABC with its sides 5/9 of the corresponding sides of ∆ABC, first draw a ray BX such that ∠CBX is an acute angle and X lies on the opposite side of A with respect to BC. Then locate points B₁, B₂, B₃, ... on BX at equal distances and next step is to join

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 11

NCERT Exemplar Class 10 Maths Exercise 10.1 Problem 4

To construct a triangle similar to a given ∆ABC with its sides 3/7 of the corresponding sides of ∆ABC, first draw a ray BX such that ∠CBX is an acute angle and X lies on the opposite side of A with respect to BC. Then locate points B₁ , B₂ , B₃ , ... on BX at equal distances and next step is to join a. B₁₀ to C, b. B₃ to C, c. B₇ to C, d. B₄ to C

Summary:

To construct a triangle similar to a given ∆ABC with its sides 3/7 of the corresponding sides of ∆ABC, first draw a ray BX such that ∠CBX is an acute angle and X lies on the opposite side of A with respect to BC. Then locate points B₁ , B₂ , B₃ , ... on BX at equal distances and the next step is to join B₇ to C

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