There is a 3 × 3 × 3 cube which consists of twenty seven 1 × 1 × 1 cubes. It is ‘tunneled’ by removing cubes from the coloured squares. Find:
i) Fraction of number of small cubes removed to the number of small cubes left in given cube
ii) Fraction of the number of small cubes removed to the total number of small cubes
iii) What part is (ii) of (i)
Solution:
To solve the above problem we will follow the fraction rules and we will answer the sections individually.
i) Number of small cubes removed = 1 + 1 + 1 + 1 + 1 + 1 + 1 = 7. Therefore, required fraction = 7/20.
ii) If the fraction of the number of small cubes is removed from the total number of small cubes then the required fraction = 7/27
iii) The required part is = 7/27 ÷ 7/20 = 20/27.
✦ Try This: There is a 4 × 4 × 4 cube which consists of sixty-four 1 × 1 × 1 cubes. Find the fraction of the number of small cubes removed from each corner to the number of small cubes left in the given cube.
☛ Also Check: NCERT Solutions for Class 7 Maths Chapter 2
NCERT Exemplar Class 7 Maths Chapter 2 Solved Ex 26
There is a 3 × 3 × 3 cube which consists of twenty seven 1 × 1 × 1 cubes (see Fig). It is ‘tunneled’ by removing cubes from the coloured squares. Find: i. Fraction of number of small cubes removed to the number of small cubes left in a given cube. ii. Fraction of the number of small cubes removed to the total number of small cubes. iii. What part is (ii) of (i)
Summary:
On applying fraction rules we have,
i) 7/20
ii) 7/27
iii) 20/27
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