The zeroes of the quadratic polynomial x² + 99x + 127 are
a. both positive
b. both negative
c. one positive and one negative
d. both equal

Solution:

Given, the quadratic polynomial is x² + 99x + 127

We have to find the zeros of the polynomial.

Using the quadratic formula,

x = [-b ± √b² - 4ac]/ 2a

Here, a = 1, b = 99 and c = 127.

x = [-99 ± √99² - 4(1) (127)]/ 2(1)

x = [-99 ± √(9801 - 508)]/ 2

x = [-99 ± √9293]/2

x = [-99 ± 96.4]/2

Now, x = (-99 + 96.4)/ 2 = -2.6/2 = -1.3

x = (-99 - 96.4)/ 2 = -195.4/ 2 = -97.7

The roots are -1.3 and -97.7.

Therefore, the zeros of the polynomial are both negative.

✦ Try This: The zeroes of the quadratic polynomial x² + 9x + 12 are

1. both positive
2. both negative
3. one positive and one negative
4. both equal

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 2

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NCERT Exemplar Class 10 Maths Exercise 2.1 Problem 7

The zeroes of the quadratic polynomial x² + 99x + 127 are a. both positive b. both negative c. one positive and one negative d. both equal

Summary:

The zeroes of the quadratic polynomial x² + 99x + 127 are both negative

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