The volumes of the two spheres are in the ratio 64 : 27. Find the ratio of their surface areas.
Solution:
Given, the ratio of the volume of two spheres is 64 : 27
We have to find the ratio of their surface areas.
Volume of sphere = 4/3 πr³
Where, r is the radius of the sphere
Volume of first sphere = 4/3 πr³
Volume of second sphere = 4/3 πR³
Given, 4/3 πr³ : 4/3 πR³ = 64 : 27
r³ : R³ = 64 : 27
Taking cubic root,
r : R = 4 : 3
Now, radius of first sphere, r = 4 units
Radius of second sphere = 3 units
Surface area of sphere = 4πr²
Where, r is the radius of the sphere
Surface area of first sphere = 4π(4)²
= 4π(16)
= 64π square units
Surface area of first sphere = 4π(3)²
= 4π(9)
= 36π square units
Ratio of surface area = 64π : 36π
= 64 : 36
= 16 : 9
Therefore, the ratio of the surface area is 16 : 9
✦ Try This: The volumes of the two spheres are in the ratio 125 : 64. Find the ratio of their surface areas.
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 13
NCERT Exemplar Class 9 Maths Exercise 13.4 Problem 5
The volumes of the two spheres are in the ratio 64 : 27. Find the ratio of their surface areas.
Summary:
The volumes of the two spheres are in the ratio 64 : 27. The ratio of their surface areas is 16 : 9
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