The value of (sin 45° + cos 45°) is
a. 1/√2
b. √2
c. √3/2
d. 1

Solution:

We have to find the value of (sin 45° + cos 45°)

Using the trigonometric identities,

sin 45° = 1/√2

cos 45° = 1/√2

Now, (sin 45° + cos 45°) = 1/√2 + 1/√2

= 2/√2

= √2

Therefore, the value of (sin 45° + cos 45°) is √2.

✦ Try This: The value of (sin 45° + tan 45°) is

We have to find the value of (sin 45° + tan 45°)

From the trigonometric identities,

sin 45° = 1/√2

tan 45° = 1

(sin 45° + tan 45°) = 1/√2 + 1

= (1 + √2)/√2

Therefore, the value of (sin 45° + tan 45°) is (1 + √2)/√2.

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 8

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NCERT Exemplar Class 10 Maths Exercise 8.1 Sample Problem 3

The value of (sin 45° + cos 45°) is a. 1/√2, b. √2, c. √3/2, d. 1

Summary:

Trigonometric identities are equations that relate to different trigonometric functions and are true for any value of the variable that is there in the domain.The value of (sin 45° + cos 45°) is √2

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