The value of p for 51² - 49² = 100p is 2. Is the given statement true or false
Solution:
The statement ‘The value of p for 51² - 49² = 100p is 2’ is true.
Given, 51² - 49² = 100p
51² - 49²
Using standard identity : a2 - b2 = (a + b) (a - b)
Here, a = 51 and b = 49,
51² - 49² = 100 p
(51 + 49) (51 - 49) = 100 p
100 × 2 = 100 p
200 = 100 p
p = 2
✦ Try This: State true or false: The value of ‘t’ for 271² - 29² = 24200t is 3
The statement The value of ‘t’ for 271² - 29² = 24200t is 3 is true
Given, 271² - 29² = 24200t
We have the identity: a² - b² = (a - b) (a + b)
Here a = 271 and b = 29
∴ 271² - 29² = (271 - 29) (271 + 29)
= 242 × 300
= 24200 × 3
∴ t = 3
☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9
NCERT Exemplar Class 8 Maths Chapter 7 Problem 78
The value of p for 51² - 49² = 100p is 2. Is the given statement true or false
Summary:
The statement ‘The value of p for 51² - 49² = 100p is 2’ is true
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