The value of [3⁻¹ × 4⁻¹]² is _________. Fill in the blank to make the statement true.

Solution:

Given, the value of [3^-1 × 4^-1]² is _________.

Using the law of exponents,

a^-n = 1/aⁿ

So, 4^-1 = 1/4

Similarly, 3^-1 = 1/3

Now, 3^-1 × 4^-1 = 1/3 × 1/4

= 1/12

[3^-1 × 4^-1]² = (1/12)²

= 1/144

Therefore, the required value is 1/144.

✦ Try This: The value of [2^-1 × 3^-1]² is _________. Fill in the blank to make the statement true.

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 12

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NCERT Exemplar Class 8 Maths Chapter 8 Problem 60

The value of [3⁻¹ × 4⁻¹]² is _________. Fill in the blank to make the statement true.

Summary:

The value of [3⁻¹ × 4⁻¹]² is 1/144 makes the statement true

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☛ Related Questions:

• The value of [2⁻¹ × 3⁻¹]⁻¹ is _________. Fill in the blank to make the statement true
• By solving (6⁰ - 7⁰) × (6⁰ + 7⁰) we get ________. Fill in the blank to make the statement true
• The expression for 3⁵ with a negative exponent is _________. Fill in the blank to make the statement . . . .