The value of [1⁻² + 2⁻² + 3⁻²] × 6² is ________ . Fill in the blank to make the statement true.

Solution:

Given, the value of [1⁻² + 2⁻² + 3⁻²] × 6² is ________ .

Using the law of exponents,

a⁻ⁿ = 1/aⁿ

So, 1⁻² = 1/1² = 1

Similarly, 2⁻² = 1/2² = 1/4

3⁻² = 1/3² = 1/9

Now, 1⁻² + 2⁻² + 3⁻² = 1/1 + 1/4 + 1/9

= (36 + 9 + 4)/36

= 49/36

We know, 6² = 36

So, [1⁻² + 2⁻² + 3⁻²] × 6² = (49/36) × 36

= 49

Therefore, the required value is 49.

✦ Try This: The value of [1⁻² + 3⁻² + 4⁻²] × 5² is ________ . Fill in the blank to make the statement true.

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 12

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NCERT Exemplar Class 8 Maths Chapter 8 Problem 65

The value of [1⁻² + 2⁻² + 3⁻²] × 6² is ________ . Fill in the blank to make the statement true.

Summary:

The value of [1⁻² + 2⁻² + 3⁻²] × 6² is 49 makes the statement true.

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☛ Related Questions:

• The multiplicative inverse of (-4)⁻² is (4)⁻². State whether the statement is true or false
• The multiplicative inverse of (3/2)² is not equal to (2/3)⁻². State whether the statement is true o . . . .
• 10⁻² = 1/100. State whether the statement is true or false