The usual form of 1000a + 10b + c is
(a) abc
(b) abc0
(c) a0bc
(d) ab0c

Solution:

The usual form of 1000a + 10b + c is a0bc

1000a + 10b + c can also be written as:

a × 10³ + 0 × 10² + b × 10¹ + c × 10⁰

Zero(0) is in the hundreds place.

The correct choice is (c)

✦ Try This: The usual form of 1000a + 100b + c is (a) abc, (b) abc0, (c) a0bc, (d) ab0c

The usual form of 1000a + 100b + c is ab0c

1000a + 100b + c can also be written as:

a × 10³ + b × 10² + 0 × 10¹ + c × 10⁰

Zero(0) is in the tens place.

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 16

---

NCERT Exemplar Class 8 Maths Chapter 13 Problem 3

The usual form of 1000a + 10b + c is (a) abc, (b) abc0, (c) a0bc, (d) ab0c

Summary:

The usual form of 1000a + 10b + c is a0bc.

---

☛ Related Questions:

• Let abc be a three-digit number. Then abc - cba is not divisible by (a) 9, (b) 11, (c) 18, (d) 33
• The sum of all the numbers formed by the digits x, y and z of the number xyz is divisible by (a) 11, . . . .
• A four-digit number aabb is divisible by 55. Then possible value(s) of b is/are (a) 0 and 2, (b) 2 a . . . .