The sum of successive odd numbers 1, 3, 5, 7, 9, 11, 13 and 15 is
a. 81
b. 64
c. 49
d. 36

Solution:

Given, the successive odd numbers are 1, 3, 5, 7, 9, 11, 13 and 15.

We have to find the sum of successive odd numbers.

We know that the sum of first n odd natural numbers is n².

Here, n = 8

n² = 8²

= 64

Verification:

Sum of successive odd numbers = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15

= 25 + 24 + 15

= 49 + 15

= 64

Therefore, the required sum is 64.

✦ Try This: The sum of successive odd numbers 1, 3, 5, 7, 9, 11, 13, 15, 17 and 19 is a. 100, b. 64, c. 49, d. 36

☛ Also Check: NCERT Solutions for Class 8 Maths

NCERT Exemplar Class 8 Maths Chapter 3 Problem 11

The sum of successive odd numbers 1, 3, 5, 7, 9, 11, 13 and 15 is, a. 81, b. 64, c. 49, d. 36

Summary:

The sum of successive odd numbers 1, 3, 5, 7, 9, 11, 13 and 15 is 64

☛ Related Questions:

• The sum of first n odd natural numbers is, a. 2n+1, b. n², c. n²–1, d. n²+1
• Which of the following numbers is a perfect cube? a. 243, b. 216, c. 392, d. 8640
• The hypotenuse of a right triangle with its legs of lengths 3x × 4x is, a. 5x, b. 7x, c. 16x, d. 25x