The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then the area of the triangle is
a. 1322 cm²
b. 1311 cm²
c. 1344 cm²
d. 1392 cm²

Solution:

Given, the sides of a triangle are 56 cm, 60 cm and 52 cm long.

We have to find the area of the triangle

Given, a = 56 cm

b = 60 cm

c = 52 cm

By Heron’s formula,

Area of triangle = √s(s - a)(s - b)(s - c)

Where s= semiperimeter

s = (a + b + c)/2

Now, s = (56 + 60 + 52)/2

= 168/2

s = 84 cm

Area of triangle = √[84(84 - 56)(84 - 60)(84 - 52)]

= √[84(28)(24)(32)]

= √[12 × 7 × 7 × 4 × 12 × 2 × 16 × 2]

= 12 × 7 × 2 × 2 × 4

= 12 × 7 × 4 × 4

= 12 × 7 × 16

= 1344 cm²

Therefore, area of triangle is 1344 cm²

✦ Try This: The sides of a triangle are 36 cm, 40 cm and 52 cm long. Then the area of the triangle is

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 12

---

NCERT Exemplar Class 9 Maths Exercise 12.1 Problem 3

The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then the area of the triangle is a. 1322 cm², b. 1311 cm², c. 1344 cm², d. 1392 cm²

Summary:

The sides of a triangle are 56 cm, 60 cm and 52 cm long. Then the area of the triangle is 1344 cm²

---

☛ Related Questions:

• The area of an equilateral triangle with side 2√3 cm is a. 5.196 cm², b. 0.866 cm², c. 3.496 cm², d. . . . .
• The length of each side of an equilateral triangle having an area of 9√3 cm² is a. 8 cm, b. 36 cm, c . . . .
• If the area of an equilateral triangle is 16√3 cm² , then the perimeter of the triangle is a. 48 cm, . . . .