The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is
a. 4950 cm²
b. 4951 cm²
c. 4952 cm²
d. 4953 cm²

Solution:

It is given that

Radius of the top of bucket = 28 cm

Radius of the bottom of bucket = 7 cm

Slant height of bucket = 45 cm

So the bucket is in the form of frustum of cone

We know that

Curved surface area of bucket = π l (R + r)

= π × 45 (28 + 7)

By further calculation

= π × 45 × 35

= 22/7 × 45 × 35

= 4950 cm²

Therefore, the curved surface area of the bucket is 4950 cm².

✦ Try This: The radii of the top and bottom of a bucket of slant height 55 cm are 35 cm and 10 cm, respectively. The curved surface area of the bucket is

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 13

NCERT Exemplar Class 10 Maths Exercise 12.1 Problem 13

The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is a. 4950 cm², b. 4951 cm², c. 4952 cm², d. 4953 cm²

Summary:

The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is 4950 cm²

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