The points A (9, 0), B (9, 6), C (–9, 6) and D (–9, 0) are the vertices of a
a. square
b. rectangle
c. rhombus
d. trapezium

Solution:

The image formed from the given points is

By using the distance formula between two points

AB = √(9 - 9)² + (6 - 0)² = 6

BC = √(9 - (-9))² + (6 - 6)² = 18

CD= √(-9 - (-9))² + (6 - 0)² = 6

AD = √(9 - (-9))² + (0 - 0)² = 18

As AB = CD and BC = AD, the points represent the vertices of a rectangle.

Therefore, the given points are the vertices of a rectangle.

✦ Try This: The points A (3, 0), B (3, 2), C (-3, 2) and D (-3, 0) are the vertices of a

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 7

NCERT Exemplar Class 10 Maths Exercise 7.1 Sample Problem 3

The points A (9, 0), B (9, 6), C (–9, 6) and D (–9, 0) are the vertices of a a. square , b. rectangle, c. rhombus, d. trapezium

Summary:

The points A (9, 0), B (9, 6), C (–9, 6) and D (–9, 0) are the vertices of a rectangle

☛ Related Questions:

• The distance of the point P (2, 3) from the x-axis is a. 2, b. 3, c. 1, d. 5
• The distance between the points A (0, 6) and B (0, –2) is a. 6 ,b. 8, c. 4, d. 2
• The distance of the point P (–6, 8) from the origin is a. 8, b. 2 √7, c. 10, d. 6