The point which lies on the perpendicular bisector of the line segment joining the points A (–2, –5) and B (2, 5) is
a. (0, 0)
b. (0, 2)
c. (2, 0)
d. (–2, 0)

Solution:

We know that

The coordinates of the mid-point of the line segment joining the point P (x₁, y₁) and Q (x₂, y₂) are

[(x₁ + x₂)/2, (y₁ + y₂)/2]

The points given are A (-2, -5) and B (2, 5)

Now by substituting the values in the formula

= [(-2 + 2)/2, (-5 + 5)/2]

= (0/2, 0/2)

= (0, 0)

Therefore, the point which lies on the perpendicular is (0, 0).

✦ Try This: The point which lies on the perpendicular bisector of the line segment joining the points A (-4, -7) and B (4, 7) is a. (0, 0), b. (0, 2), c. (2, 0), d. (-2, 0)

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 7

NCERT Exemplar Class 10 Maths Exercise 7.1 Problem 10

The point which lies on the perpendicular bisector of the line segment joining the points A (–2, –5) and B (2, 5) is a. (0, 0), b. (0, 2), c. (2, 0), d. (–2, 0)

Summary:

The point which lies on the perpendicular bisector of the line segment joining the points A (–2, –5) and B (2, 5) is (0, 0)

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