The point of the form (a, -a) always lies on the line
a. x = a
b. y = -a
c. y = x
d. x + y = 0
Solution:
The point given is of the form (a, -a)
Here both x and y coordinate values are the different
So it must lie on the line x + y = 0
Therefore, the point lies on the line x + y = 0.
✦ Try This: The graph of the linear equation 4x + 5y = 20 is a line which meets the x-axis at the point a. (0, 4), b. (4, 0), c. (5, 0), d. (0, 5)
An equation that has the highest degree of 1 is known as a linear equation.
It means that no variable in a linear equation has an exponent more than 1.
The given linear equation is 4x + 5y = 20
It meets the x-axis which means that y = 0
Let us substitute it in the equation
4x + 5(0) = 20
4x = 20
Dividing both sides by 4
x = 5
Therefore, the graph of the linear equation is (5, 0).
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 4
NCERT Exemplar Class 9 Maths Exercise 4.1 Problem 19
The point of the form (a, -a) always lies on the line a. x = a, b. y = -a, c. y = x, d. x + y = 0
Summary:
The point of the form (a, -a) always lies on the line x + y = 0 as the x and y coordinates are different
☛ Related Questions:
- ax + by + c = 0, where a, b and c are real numbers, is a linear equation in two variables. Is the gi . . . .
- A linear equation 2x + 3y = 5 has a unique solution. Is the given statement true or false? Justify y . . . .
- All the points (2, 0), (-3, 0), (4, 2) and (0, 5) lie on the x-axis. Is the given statement true or . . . .
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