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The overall width in cm of several wide-screen televisions are 97.28 cm, 98 4/9cm, 98 1/25 cm and 97.94 cm. Express these numbers as rational numbers in the p/q form and arrange the widths in ascending order.

Solution:

TV1 width = 97.28cm =9728/100= 2432/25

TV2 width = 98 4/9cm = 886/9 = 88.2

TV3 width = 98 1/25cm = 2451/25 = 98

TV4 width = 97.94cm = 9794/100=4897/50

By comparing the numbers in decimals, we can say that

Ascending order is TV2 < TV1 < TV4 < TV3

✦ Try This: The overall width in cm of several wide-screen televisions are 101.38 cm, 90 1/9cm, 99 1/5 cm and 87.64 cm. Express these numbers as rational numbers in the p/q form and arrange the widths in ascending order.

TV1 width = 101.38cm = 5069/50

TV2 width = 90 1/9cm = 811/9 = 90.11

TV3 width = 99 1/5cm = 496/5 = 99.2

TV4 width = 87.64cm = 2191/25

Ascending order is TV4 < TV2 < TV3 < TV1

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 1

NCERT Exemplar Class 8 Maths Chapter 1 Problem 147

The overall width in cm of several wide-screen televisions are 97.28 cm, 98 4/9cm, 98 1/25 cm and 97.94 cm. Express these numbers as rational numbers in the p/q form and arrange the widths in ascending order

Summary:

The overall width in cm of several wide-screen televisions are 97.28 cm, 98 4/9cm, 98 1/25 cm and 97.94 cm. Expressed these numbers as rational numbers in the p/q form as 2432/25, 886/9, 2451/25, 4897/50 and arranged the widths in ascending order as TV2 < TV1 < TV4 < TV3

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