The mid-points D, E, F of the sides of a triangle ABC are (3, 4), (8, 9) and (6, 7). Find the coordinates of the vertices of the triangle
Solution:
Given, the midpoints of sides of ∆ ABC are D(3, 4) E(8, 9) and F(6, 7)
We have to find the coordinates of the vertices of the ∆ ABC.
Let A = (x₁, y₁) B = (x₂, y₂) and C(x₃, y₃)
The coordinates of the mid-point of the line segment joining the points P (x₁ , y₁) and Q (x₂ , y₂) are [(x₁ + x₂)/2, (y₁ + y₂)/2]
Midpoint of AB = D
[(x₁ + x₂)/2, (y₁ + y₂)/2] = (3, 4)
Now, (x₁ + x₂)/2 = 3
x₁ + x₂ = 6 ----------- (1)
Also, (y₁ + y₂)/2 = 4
y₁ + y₂ = 8 ------------ (2)
Midpoint of BC = E
[(x₂ + x₃)/2, (y₂ + y₃)/2] = (8, 9)
Now, (x₂ + x₃)/2 = 8
x₂ + x₃ = 16 ------------------ (3)
Also, (y₂ + y₃)/2 = 9
y₂ + y₃ = 18 -------------------- (4)
Midpoint of AC = F
[(x₁ + x₃)/2, (y₁ + y₃)/2] = (6, 7)
Now, (x₁+x₃)/2 = 6
x₁ + x₃ = 12 ---------------- (5)
Also, (y₁ + y₃)/2 = 7
y₁ + y₃ = 14 ---------------- (6)
Adding (1), (3) and (5) we get,
2(x₁ + x₂ + x₃) = 6 + 16 + 12
2(x₁ + x₂ + x₃) = 34
x₁ + x₂ + x₃ = 17 --------------- (7)
Substitute (1) in (7),
6 + x₃ = 17
x₃ = 11
Substitute (2) in (7),
x₁ + 16 = 17
x₁ = 17 - 16
x₁ = 1
Substitute (3) in (7),
x₂ + 12 = 17
x₂ = 17 - 12
x₂ = 5
Adding (2), (4) and (6) we get,
2(y₁ + y₂ + y₃) = 8 + 18 + 14
2(y₁ + y₂ + y₃) = 40
y₁ + y₂ + y₃ = 20 ------------------ (8)
Substitute (2) in (8),
8 + y₃ = 20
y₃ = 20 - 8
y₃ = 12
Substitute (4) in (8),
y₁ + 18 = 20
y₁ = 20 - 18
y₁ = 2
Substitute (6) in (8),
y₂ + 14 = 20
y₂ = 20 - 14
y₂ = 6
Therefore, the vertices of ∆ ABC are A(1, 2) B(5, 6) and C(11, 12).
✦ Try This: The mid-points of the sides of a triangle are (4, 5), (6, 7) and (3, 4). Find the coordinates of the vertices of the triangle.
☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 7
NCERT Exemplar Class 10 Maths Exercise 7.4 Sample Problem 1
The mid-points D, E, F of the sides of a triangle ABC are (3, 4), (8, 9) and (6, 7). Find the coordinates of the vertices of the triangle
Summary:
The mid-points D, E, F of the sides of a triangle ABC are (3, 4), (8, 9) and (6, 7). The coordinates of the vertices of the triangle are A(1, 2) B(5, 6) and C(11, 12)
☛ Related Questions:
- If D(-1/2, 5/2) E(7, 3) and F(7/2, 7/2) are the midpoints of sides of ∆ ABC, find the area of the ∆ . . . .
- The points A (2, 9), B (a, 5) and C (5, 5) are the vertices of a triangle ABC right angled at B. Fin . . . .
- Find the coordinates of the point R on the line segment joining the points P (–1, 3) and Q (2, 5) su . . . .
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