The mean of five numbers is 30. If one number is excluded, their mean becomes 28. The excluded number is :
a. 28
b. 30
c. 35
d. 38
Solution:
Consider x1, x2, x3, x4, x5 as the five numbers and one of the excluded number is x5
It is given that
Mean of five numbers = 30
We can write it as
(x1 + x2 + x3 + x4 + x5)/5 = 30
x1 + x2 + x3 + x4 + x5 = 150
x1 + x2 + x3 + x4 = 150 - x5
Divide both sides by 4
(x1 + x2 + x3 + x4)/4 = (150 - x5)/4 …. (1)
It is given that
Mean of four numbers = 28
(150 - x5)/4 = 28 from equation (1)
By cross multiplication
150 - x5 = 112
By further calculation
x5 = 150 - 112
x5 = 38
Therefore, the excluded number is 38.
✦ Try This: The mean of five numbers is 20. If one number is excluded, their mean becomes 18. The excluded number is :
☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 14
NCERT Exemplar Class 9 Maths Exercise 14.1 Problem 11
The mean of five numbers is 30. If one number is excluded, their mean becomes 28. The excluded number is : a. 28, b. 30, c. 35, d. 38
Summary:
The mean of five numbers is 30. If one number is excluded, their mean becomes 28. The excluded number is 38
☛ Related Questions:
- If the mean of the observations : x, x + 3, x + 5, x + 7, x + 10 is 9, the mean of the last three ob . . . .
- If x̄ represents the mean of n observations x1 , x2 , ..., xn , then value of sigma i = 1 to n (xi - . . . .
- If each observation of the data is increased by 5, then their mean a. remains the same, b. becomes 5 . . . .
visual curriculum