The largest number which divides 70 and 125, leaving remainders 5 and 8, respectively, is
a. 13
b. 65
c. 875
d. 1750

Solution:

Given,

5 and 8 are the remainder of 70 and 125.

Subtracting these remainders from the given numbers,

we get (70 - 5) = 65, (125 - 8) = 117

Which are divisible by the required number.

Required number = HCF of 65 and 117.

117 = 65 × 1 + 52

65 = 52 × 1 + 13

52 = 13 × 4 + 0

HCF (65, 117) = 13

Therefore, 13 is the largest number

✦ Try This: What is the HCF of 4052 and 12576

☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 1

NCERT Exemplar Class 10 Maths Exercise 1.1 Problem 5

The largest number which divides 70 and 125, leaving remainders 5 and 8, respectively, is a. 13, b. 65 c. 875, d. 1750

Summary:

The largest number which divides 70 and 125, leaving remainders 5 and 8, respectively, is 13

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