The height of a triangle is x⁴ + y⁴ and its base is 14xy. Find the area of the triangle.

Solution:

Given, the height of a triangle is x⁴ + y⁴ and its base is 14xy.

The area of the triangle = 1/2 × base × height

∴ The area of the triangle = 1/2 × 14xy × (x⁴ + y⁴)

= 7xy (x⁴ + y⁴)

✦ Try This: If the two adjacent sides base and perpendicular of the right angled triangle are (3x + 5) and (x + 7) then find the area of the triangle.

Given, the two adjacent sides base and perpendicular of the right angled triangle are (3x + 5) and (x + 7).

The area of the triangle = 1/2 × base × height

∴ The area of the triangle = 1/2 × (3x + 5) × (x + 7)

= 1/2 × (3x² + 21x + 5x + 35)

= (3x² + 26x + 35) / 2

☛ Also Check: NCERT Solutions for Class 8 Maths Chapter 9

NCERT Exemplar Class 8 Maths Chapter 7 Problem 104

The height of a triangle is x⁴ + y⁴ and its base is 14xy. Find the area of the triangle.

Summary:

Given the height of a triangle is x⁴ + y⁴ and its base is 14xy, the area of the triangle is 7xy(x⁴ + y⁴)

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