The graph of the linear equation y = x passes through the point
a. (3/2, -3/2)
b. (0, 3/2)
c. (1, 1)
d. (-1/2, 1/2)

Solution:

We know that

A linear equation is an equation in which the highest power of the variable is always 1. An equation that has the highest degree of 1 is known as a linear equation.

The linear equation y = x has the same x and y coordinates

From the given option (1, 1) is the graph

Therefore, the graph of the linear equation passes through (1, 1).

✦ Try This: The graph of the linear equation 2x + 6y = 12 is a line which meets the x-axis at the point a. (0, 2), b. (2, 0), c. (6, 0), d. (0, 6)

An equation that has the highest degree of 1 is known as a linear equation.

It means that no variable in a linear equation has an exponent more than 1.

The given linear equation is 2x + 6y = 12

It meets the x-axis which means that y = 0

Let us substitute it in the equation

2x + 6(0) = 12

2x = 12

Dividing both sides by 2

x = 6

Therefore, the graph of the linear equation is (6, 0).

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 4

NCERT Exemplar Class 9 Maths Exercise 4.1 Problem 15

The graph of the linear equation y = x passes through the point a. (3/2, -3/2), b. (0, 3/2), c. (1, 1), d. (-1/2, 1/2)

Summary:

The graph of a linear equation in two variables x and y forms a straight line. The graph of the linear equation y = x passes through the point (1, 1)

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