The graph of the linear equation 2x + 3y = 6 cuts the y-axis at the point
a. (2, 0)
b. (0, 3)
c. (3, 0)
d. (0, 2)

Solution:

The given linear equation is

2x + 3y = 6

It is given that the equation cuts the y-axis which means that x-coordinate is 0

Substituting x = 0 in the linear equation

2 (0) + 3y = 6

0 + 3y = 6

3y = 6

Dividing both sides by 3

y = 2

So the coordinates are (0, 2)

Therefore, the graph of the linear equation cuts the y-axis at the point (0, 2).

✦ Try This: The graph of the linear equation 5x + 6y = 30 cuts the y-axis at the point a. (5, 0), b. (0, 6), c. (6, 0), d. (0, 5)

☛ Also Check: NCERT Solutions for Class 9 Maths Chapter 4

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NCERT Exemplar Class 9 Maths Exercise 4.1 Problem 5

The graph of the linear equation 2x + 3y = 6 cuts the y-axis at the point a. (2, 0), b. (0, 3), c. (3, 0), d. (0, 2)

Summary:

Linear equations are algebraic equations in which each term has a real constant and the equation contains 2 variables of the highest power 1.The graph of the linear equation 2x + 3y = 6 cuts the y-axis at the point (0, 2)

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☛ Related Questions:

• The equation x = 7, in two variables, can be written as a. 1 . x + 1 . y = 7, b. 1. x + 0. y = 7, c. . . . .
• Any point on the x-axis is of the form a. (x, y), b. (0, y), c. (x, 0), d. (x, x)
• Any point on the line y = x is of the form a. (a, a), b. (0, a), c. (a, 0), d. (a, -a)